Log(16+2b)=b^2-4b

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Solution for Log(16+2b)=b^2-4b equation: 


Simplifying
Log(16 + 2b) = b2 + -4b
(16 * goL + 2b * goL) = b2 + -4b

Reorder the terms:
(2bgoL + 16goL) = b2 + -4b
(2bgoL + 16goL) = b2 + -4b

Reorder the terms:
2bgoL + 16goL = -4b + b2

Solving
2bgoL + 16goL = -4b + b2

Solving for variable 'b'.

Reorder the terms:
4b + 2bgoL + -1b2 + 16goL = -4b + b2 + 4b + -1b2

Reorder the terms:
4b + 2bgoL + -1b2 + 16goL = -4b + 4b + b2 + -1b2

Combine like terms: -4b + 4b = 0
4b + 2bgoL + -1b2 + 16goL = 0 + b2 + -1b2
4b + 2bgoL + -1b2 + 16goL = b2 + -1b2

Combine like terms: b2 + -1b2 = 0
4b + 2bgoL + -1b2 + 16goL = 0

The solution to this equation could not be determined.

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